Secret Number
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4174 Accepted Submission(s): 1719
Problem Description
有一天, KIKI 收到一张奇怪的信, 信上要KIKI 计算出给定数各个位上数字为偶数的和. eg. 5548 结果为12 , 等于 4 + 8 KIKI 很苦恼. 想请你帮忙解决这个问题.
Input
输入数据有多组,每组占一行,只有一个数字,保证数字在INT范围内.
Output
对于每组输入数据,输出一行,每两组数据之间有一个空行.
Sample Input
415326 3262
Sample Output
12 10
Author
kiki
#includeint flag; int fun(int x) { int p, sum = 0; if (flag != 1 ) puts(""); while(x) { p = x % 10; if ((p & 1) == 0) sum += p; x = x / 10; } return sum; } int main( ) { int N; flag = 0; while(scanf("%d", &N)!= EOF) { flag++; printf("%d\n",fun(N)); } return 0; }